{"id":3359,"date":"2012-08-15T12:00:24","date_gmt":"2012-08-15T15:00:24","guid":{"rendered":"http:\/\/scienceblogs.com.br\/hypercubic\/?p=3359"},"modified":"2012-08-15T12:00:24","modified_gmt":"2012-08-15T15:00:24","slug":"emende-esse-carrossel","status":"publish","type":"post","link":"https:\/\/www.blogs.unicamp.br\/hypercubic\/2012\/08\/emende-esse-carrossel\/","title":{"rendered":"Emende esse carrossel\u2026"},"content":{"rendered":"<p><img fetchpriority=\"high\" decoding=\"async\" src=\"http:\/\/scienceblogs.com.br\/hypercubic\/files\/2012\/08\/20100911-merry-go-round1.gif\" alt=\"\" width=\"676\" height=\"383\" \/><\/p>\n<p align=\"justify\">Ap\u00f3s ser promovido de <a title=\"[Enigma] Emende esse carrossel\u2026\" href=\"http:\/\/scienceblogs.com.br\/hypercubic\/2012\/08\/enigma-emende-esse-carrossel\/\" target=\"_blank\" rel=\"noopener noreferrer\">tratador de elefantes a carrosseleiro<\/a>, voc\u00ea resolve fazer uma pequena reforma no carrossel que vai cuidar. Mas antes, voc\u00ea precisa saber quanta tinta vai precisar. A \u00fanica medida que voc\u00ea conseguiu foi uma corda (geom\u00e9trica) com 13 metros de extens\u00e3o.<\/p>\n<p><!--more--><\/p>\n<p align=\"justify\">N\u00e3o \u00e9 preciso ser um g\u00eanio da geometria para resolver esse pequeno problema. At\u00e9 um ex-tratador de elefantes perceberia que a \u00e1rea do assoalho do carrossel \u00e9 igual \u00e0 \u00e1rea do c\u00edrculo maior menos a do c\u00edrculo menor.<\/p>\n<p align=\"justify\">Ou, em uma f\u00f3rmula simples: <span style=\"font-family: Georgia\"><strong>\u03c0A\u00b2 \u2013 \u03c0B\u00b2<\/strong><\/span>. Simplificando ainda mais, a \u00e1rea que voc\u00ea precisa pintar \u00e9 igual a <span style=\"font-family: Georgia\"><strong>\u03c0(A\u00b2 \u2013 B\u00b2)<\/strong><\/span>. Ou, usando a figura:<\/p>\n<p align=\"justify\"><img decoding=\"async\" style=\"display: block;float: none;margin-left: auto;margin-right: auto\" title=\"2012-08-08-horse-play-2\" src=\"http:\/\/scienceblogs.com.br\/hypercubic\/files\/2012\/08\/2012-08-08-horse-play-2.gif\" alt=\"horse play 2\" width=\"247\" height=\"320\" \/><\/p>\n<p align=\"justify\">N\u00e3o temos as medidas de <strong><span style=\"font-family: Georgia\">A<\/span><\/strong> ou <span style=\"font-family: Georgia\"><strong>B<\/strong><\/span>, mas o comprimento da corda verde \u2014 <strong>13m<\/strong> \u2014 \u00e9 o bastante. Aplicando a f\u00f3rmula pitag\u00f3rica, temos que <span style=\"font-family: Georgia\"><strong>B\u00b2 + (6,5)\u00b2 = A\u00b2<\/strong><\/span>, donde <span style=\"font-family: Georgia\"><strong>(6,5)\u00b2 = A\u00b2 \u2013 B\u00b2<\/strong><\/span>. Com a f\u00f3rmula mais simplificada, j\u00e1 achamos a resposta: a \u00e1rea do assoalho \u00e9 <span style=\"font-family: Georgia\"><strong>6,5\u00b2\u03c0 m\u00b2<\/strong><\/span>. Considerando <span style=\"font-family: Georgia\"><strong>\u03c0 = 3,14<\/strong><\/span>, isso d\u00e1 <span style=\"font-family: Georgia\"><strong>42,25 x 3,14 = 132,65 m\u00b2<\/strong><\/span>.<\/p>\n<p align=\"justify\">Como cada lata de tinta de 3,6 litros cobre 30 m\u00b2, voc\u00ea vai precisar comprar pelo menos cinco latas, pois <span style=\"font-family: Georgia\"><strong><strong>132,65<\/strong>\/30 = 4,42<\/strong><\/span>.<\/p>\n<p style=\"text-align: justify\" align=\"justify\">Como trata-se de geometria simples, todos os comentaristas acabaram concordando quanto ao resultado. Quantos \u00e0s cores n\u00e3o houve consenso, \u00e9 claro. Por\u00e9m, a maioria se decidiu por tons mais claros como marfim (escolha do pedro) ou amarelo (do murilo). \u00c9 verdade que n\u00e3o h\u00e1 certo ou errado em escolhas est\u00e9ticas, mas fica a dica: cores claras podem ser muito bonitas, mas lembrem-se que est\u00e3o pintando o assoalho de um carrossel \u2014 se escolherem cores claras, v\u00e3o ter que limp\u00e1-lo com mais frequ\u00eancia. \ud83d\ude42<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Ap\u00f3s ser promovido de tratador de elefantes a carrosseleiro, voc\u00ea resolve fazer uma pequena reforma no carrossel que vai cuidar. Mas antes, voc\u00ea precisa saber quanta tinta vai precisar. A \u00fanica medida que voc\u00ea conseguiu foi uma corda (geom\u00e9trica) com 13 metros de extens\u00e3o.<\/p>\n","protected":false},"author":486,"featured_media":3361,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_eb_attr":"","_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"material-hide-sections":[],"pgc_sgb_lightbox_settings":"","_vp_format_video_url":"","_vp_image_focal_point":[],"footnotes":""},"categories":[152],"tags":[],"class_list":["post-3359","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-geral"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.6 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Emende esse carrossel\u2026 - hypercubic<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, 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